Question

if d and b are zeros of x^2 + 5x + 8 then the value of d + b is​

Answer 1

$x^2+5x+8=0\\D=b^2-4ac\\D=5^2-4*1*8\\D=25-32\\D=-7\\d=\frac{-b+\sqrt{D} }{2a} \\Or\\b=\frac{-b-\sqrt{D} }{2a}\\d=\frac{-5+\sqrt{-7} }{2}\\b=\frac{-5-\sqrt{-7} }{2}\\d+b=\frac{-5+\sqrt{-7}-5-\sqrt{-7} }{2}\\d+b=\frac{-10}{2}\\ d+b=-5$