if d and e are the points on sides ab respectively such that abc is isosceles triangle
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Answered by
8
Answer:
PLEASE DON'T GIVE NON SENSE ANSWER..
Step-by-step explanation:
GIVEN : In Δ ABC, DE || BC and BD = CE.
To prove : Δ ABC is isosceles.
AD / BD = AE/EC
[By using basic proportionality theorem]
AD = AE
[ BD = CE ]
So, AD + BD = AE + CE.
[BD = CE & AD = AE]
Therefore, AB = AC.
~Hence, Δ ABC is isosceles.
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Answered by
3
Step-by-step explanation:
GIVEN : In Δ ABC, DE || BC and BD = CE.
To prove : Δ ABC is isosceles.
AD / BD = AE/EC
[By using basic proportionality theorem]
AD = AE
[ BD = CE ]
i
So, AD + BD = AE + CE.
[BD = CE & AD = AE]
Therefore, AB = AC.
~Hence, Δ ABC is isosceles.
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