If D, E, and F are mid points of the sides AB, BC, and CA respectively of an isosceles triangle ABC, prove that Δ DEF is also isosceles.
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Step-by-step explanation:
Given: D,E,F are the mid points of
AB,BC,CA
To Prove: DE = EF
Proof: AB = AC (isosceles triangle) ZB = ZC (angle opp to equal sides)
1/2 AB = 1/2 AC so,DB = CF
In AADF and ACEF
DB = CF (proved above)
BE = CE (E is the mid point of BC)
ZB = LC (proved above) .. AADF = ACEF (SAS)
DE = FE (CPCT)
Hence, Proved
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