If d equation mx 2 + 2x + m = 0 has 2 equal roots find m.
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mx^2+2x+m=0
we have a=m, b=2 and c=m
D=b^2-4ac
=(2)^2-4*m*m
=4-4m^2
D=0 when equal roots.
4-4m^2=0
4=4m^2
m^2=1
m=+1,-1
we have a=m, b=2 and c=m
D=b^2-4ac
=(2)^2-4*m*m
=4-4m^2
D=0 when equal roots.
4-4m^2=0
4=4m^2
m^2=1
m=+1,-1
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