Math, asked by Anonymous, 5 months ago

If d = HCF (48, 72), then find the value of d

Answers

Answered by Naolin
25

Answer:

24

Step-by-step explanation:

By Prime Factorization

48 = 2^4 x 3

72 = 2³ x 3²

HCF = 2³ x 3

        = 8 x 3

        = 24

∴ The HCF of 48 and 72 is 24

We know that,

d=HCF (Given in question)

So,

d=24

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Answered by XxLuckyGirIxX
230

\bf\pink{QuestioN:-}

If d = HCF (48, 72), then find the value of d.

\bf\blue{AnsweR:-}

According to the given condition,

\longmapsto\bf{d=HCF\:(48,72)}

By prime factorization method,

\longmapsto\bf{48=2\times2\times2\times2\times3}

\longmapsto\bf{48=2^4\times3}

\longmapsto\bf{72=2\times2\times2\times3\times3}

\longmapsto\bf{72=2^3\times3^2}

For finding HCF, we want to consider the smallest common multiples here.

That is,

\longmapsto\bf{HCF=2\times2\times2\times3}

\longmapsto\bf{HCF=2^3\times3}

\longmapsto\bf{HCF=24}

So the HCF is 24.

As per the question,

\longmapsto\bf{HCF=d=24}

•°• d = 24, the value of d is 24.

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