if d=hcf(48,80).find d
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d is the 16 which is the hcf of 48,80
Aakashkhan:
how
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D is the hcf of 48 amd 80.
So 48 = 2 × 2×2×2×3
80 = 2 × 2 ×2×2×5
So hcf is the highest common factor
So hcf(48,80) = 16
So 48 = 2 × 2×2×2×3
80 = 2 × 2 ×2×2×5
So hcf is the highest common factor
So hcf(48,80) = 16
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