If D is a point on the side AB of ∆ABC such that AD:DB= 5:2 and E is a point on BC such that BD || AC. The ratio of the areas of ∆ ABC and ∆ DBC is
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ADDB = 32 [ Given ] ADDB + 1 = 32 + 1 AD + DBDB = 3 + 22 ABDB = 52 - - - (1)In BDE and ABC B = B [ Common ] BAC = BDE [ DE∥ AC ] ABC∼ BDE [ By AA similarity ...
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