Question

if d is HCF of 40and 65,find the
value of integers X and Y which
satisfy d=40x 65y

Answer 1

since hcf of 40,65 is 5...value of d=5.

5=40 x 65y (since d=5)

5=2600y

5/2600 = y

y = 1/520 (0.001923 )