if d is HCF of 40and 65,find the
value of integers X and Y which
satisfy d=40x+65y i am not getting the answer !!!
Answers
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D is the hcf of 40 and 65
So d= 5
Now
D=40x+65y
5=5 (8x+13y)
So
1= 8x+13y
Or
1-8x=13y
It is a two variable linear equation so it has an infinite solution.
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