If d is the distance between the slits and the screen in young's double slit experiment and the two slits are separated by a distance equal to twice of the wave length, then the fringe width will be
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Fringe width=lamda×D/d
Where,
Lamda is the wavelength associated
D is the distance between the slits and the screen
and d is the distance between slits
Frimge width=lamda×D/2lamda
=D/2
I hope this helps
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The slit separation and the distance between the wall and the slits did have an effect on the interference pattern. ... As the number of slits increased, the fringe width would also increase, because with more slits, the more slits the light waves could travel through, and more interference could occur.
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