Question

If 'd' is the H.C.F of 45 and 27,find x and y satisfying d=27x+45y​

Answer 1

$\large \mathtt \purple{Solution :-}$

HCF of 45 and 27 can be calculated as follows.

45 = 27 x 1 + 18

27 = 18 x 1 + 9

18 = 9 x 2 + 0

So, HCF (45, 27) = 9

d = 9 = 27x + 45y

From above steps, we have:-

9 = 27 - 18 x 1

= 27 - (45 - 27 x 1) x 1

= 27 x 2 + 45 (-1)

Comparing this with given relation, we get,

x = 2 and y = -1

Answer 2

$\large\mapsto\boxed{ \sf \green{ѕσlutíσn}} \:$

HCF of 45 and 27 can be calculated as follows.

45 = 27 x 1 + 18

27 = 18 x 1 + 9

18 = 9 x 2 + 0

So, HCF (45, 27) = 9

d = 9 = 27x + 45y

From above steps, we have:-

9 = 27 - 18 x 1

= 27 - (45 - 27 x 1) x 1

= 27 x 2 + 45 (-1)

Comparing this with given relation, we get,

x = 2 and y = -1