If ‘d ‘ is the H.C.F of 963 & 657, Find the value of x & y satisfying d = 963x + 657y.
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answer : x = -15 and y = 22
d is the HCF of 963 and 657 .
prime factors of 963 = 3 × 3 × 107
prime factors of 657 = 3 × 3 × 73
HCF of 963 and 657 = highest common factors of 963 and 657 = 3 × 3
⇒d = 9
given, d = 963x + 657y
⇒9 = 963x + 657y
⇒1 = 107x + 73y.......(1)
putting x = -15 and y = 22
⇒1 = 107 × (-15) + 73 × 22
hence x = -15 and y = 22
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x = -15
y = 22
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