Math, asked by kaustubhsy, 11 months ago

if d is the HCF of 1032 and 408,find x,y satisfying d=1032x+408y​

Answers

Answered by MANTUMEHER
0

Answer:

x=1/86. y=1/34

Step-by-step explanation:

as the HCF is 24 for this value the value of x and y are respectively 1/86 and 1/34

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