Math, asked by maimunahmed2, 6 months ago

If ‘d’ is the HCF of 272 and 1032. Find (x, y) satisfying d = 272x + 1032y

Answers

Answered by mbakshi37

0

Answer:

1/17; 2/129

if f is a Factor ( say HCF of 272 and 1032 ) then x and y can only be relevant fractions of Non " D factors of 272 and 1032.

so D is 6

hence X is 1/17 = 2D / 272

and y is 2/129 = 2D/ 1032

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