if d is the hcf of 30,72 find the value of x and y satisfying d=3
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By Euclid Division Lemma
a=bq + r
b=3
r=0,1,2
Case 1=3072=3*x+0
=3072/3=x =x=1024
=3072=3*1024+y
=y=0
x=1024 :y=0
I Hope this will be correct
a=bq + r
b=3
r=0,1,2
Case 1=3072=3*x+0
=3072/3=x =x=1024
=3072=3*1024+y
=y=0
x=1024 :y=0
I Hope this will be correct
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