if d is the HCF of 30and72 find the values of x and y satisfying d=30x+72y also show that x and y are not unique
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Answered by
4
Hi friend,
Euclid division lemma:-
a = bq + r
0 ≤ r < b
a > b
72 = 30 × 2 + 12
30 = 12 × 2 + 6
12 = 6 × 2 + 0
As the remainder is 0,we can not proceed further.
HCF (30,72) = 6
d = 6
6 = 30 - 12×2
=30 - {72-30(2)}×2
= 30 - 72×2+30×4
= 30×5 - 72×2
= 30×5 + 72×(-2)
= 30x + 72 y
x = 5 and y = -2
Therefore, x and y are not unique.
Hope it helps
Euclid division lemma:-
a = bq + r
0 ≤ r < b
a > b
72 = 30 × 2 + 12
30 = 12 × 2 + 6
12 = 6 × 2 + 0
As the remainder is 0,we can not proceed further.
HCF (30,72) = 6
d = 6
6 = 30 - 12×2
=30 - {72-30(2)}×2
= 30 - 72×2+30×4
= 30×5 - 72×2
= 30×5 + 72×(-2)
= 30x + 72 y
x = 5 and y = -2
Therefore, x and y are not unique.
Hope it helps
Answered by
1
Factors of 30=2×3×5
Factors of 72=2×2×2×3×3
Highest Common factor=2×3=6=d
i→x=1/5,y=0
ii→x=0,y=1/12
....
...
..
.
And so on❕❕❕❕
Factors of 72=2×2×2×3×3
Highest Common factor=2×3=6=d
i→x=1/5,y=0
ii→x=0,y=1/12
....
...
..
.
And so on❕❕❕❕
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