Question

IF d is the HCF of 45 and 24, find x and y staifing d=27x+45y​

Answer 1

Answer:

x=-14/9, y=1

Step-by-step explanation:

HCF of 45 and 24 is 3

putting the value of d in equation

27x + 45 y =d

27x + 45y =3

27x = 3 - 45y

x= (3 - 45y ) / 27

putting the value of x in equation

{(3-45y)/27} *27 + 45y =3

(3-45y) +45y =3

-42y +45y =3

3y =3

y=1

putting the value of y in equation

x= (3-45y)/27

x=(3-45)/27

x= -42/27

x= -14/9