If d is the hcf of 45 and 27 find x and y satiafiyng d = 27x+45y
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hcf of 45 and 27 is 135 i.e.,
d = 135 and,
135 = 27(10) + 45(-3) i.e,
x = 10
y = -3
d = 135 and,
135 = 27(10) + 45(-3) i.e,
x = 10
y = -3
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