if d is the hcf of 45 and 27,find x and y satisfying d= 27x+45y
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Answered by
411
Hello there !
The numbers are :-
45 and 27
Lets find their HCF
BY Euclid's division Lemma :-
a = bq + r
45 = 27 x 1 + 18
27 = 18 x 1 + 9
18 = 9 x 2 + 0
HCF = d = 9
Given:-
d = 27x+45y
9 = 27x + 45y
9 = 27 - 18 x 1
18 = 45 - 27 x 1
Therefore ,
9 = 27 - [ 45 x 27 x 1 ] x 1
= 27 x 2 - 45
9 = 27 x 2 + 45 x [ -1 ]
x = 2
y = -1
Hope this Helps You !
The numbers are :-
45 and 27
Lets find their HCF
BY Euclid's division Lemma :-
a = bq + r
45 = 27 x 1 + 18
27 = 18 x 1 + 9
18 = 9 x 2 + 0
HCF = d = 9
Given:-
d = 27x+45y
9 = 27x + 45y
9 = 27 - 18 x 1
18 = 45 - 27 x 1
Therefore ,
9 = 27 - [ 45 x 27 x 1 ] x 1
= 27 x 2 - 45
9 = 27 x 2 + 45 x [ -1 ]
x = 2
y = -1
Hope this Helps You !
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