If d is the HCF of 45 and 27, find x and y satisfying d=27x+45y
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hcf of 45 and 27 is 9
9 = 27x + 45y
For a two variable equation.. there are infinite solutions as for every x there is a corresponding y
so for x be 1
9 = 27(1) - 45y
9-27 = -45y
-18 = -45 y
45 y = 18
y = 18/45
= 2/5 = 0.4
You can take any value of x and take out the value of y by substituting vale of x in the equation to get your desired value.
But this infinite number of solution goes only in the case of 2 variables of only 1 equation and in 2 equations when the lines drawn on the graph draw lie on each other I.e. are co-inicident.
Hope it will help
9 = 27x + 45y
For a two variable equation.. there are infinite solutions as for every x there is a corresponding y
so for x be 1
9 = 27(1) - 45y
9-27 = -45y
-18 = -45 y
45 y = 18
y = 18/45
= 2/5 = 0.4
You can take any value of x and take out the value of y by substituting vale of x in the equation to get your desired value.
But this infinite number of solution goes only in the case of 2 variables of only 1 equation and in 2 equations when the lines drawn on the graph draw lie on each other I.e. are co-inicident.
Hope it will help
lazyguy587:
the question is actually from real numbers
so the values are quite different i suppose
but thanks anyways
real nunbers also constitute rational numbers
hope you ll mark it the brainliest
i didnt get the option to mark it as brainliest
plus now i understood
thnx a lot
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