Question

If d is the HCF of 45 and 27, find x, y satisfying d=27x + 45 y

Answer 1

Answer:

x =5, y=-3,& x=-5 ,y=3

Step-by-step explanation:

HCF OF 45 AND 27 IS =9

9 =27X+45Y

9= 9(3X+5Y)

0= 3X+5Y

PUT VALUE OF X=-5 AND Y=3

0= -15+15=