Question

If d is the HCF of 56 and 72, find x, y satisfying d = 56x + 72y. Also show that x and y is not unique.​

Answer 1

Answer:

$d = 8$

$8 = 56x + 72y$

$8 = 8(7x + 9y)$

$1 = 7x + 9y$

$7x = 1 - 9y$

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Answer 2

Answer:

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Step-by-step explanation:

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