If d is the Highest Common Factor of 32 and 60, find x and y satisfying d = 32x + 60 y.
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Answer:
x = 2 and y = -1.
Step-by-step explanation:
60 > 32
60 = 32(1) + 28 ----(1)
32 = 28(1) + 4 ----(2)
28 = 4(7) + 0 ----(3)
Hence the H.C.F of 60 and 32 is 4.
d = 4
d = 32x + 60y
4 = 32 x + 60 y
From (2), let us solve for 4
4 = 32 - 28(1) ---(4)
From (1), let us solve for 28
28 = 60 - 32(1)---(5)
By applying the value of 28 from (5) into (4), we get
4 = 32 - (60 - 32(1)) ×1
4 = 32 - 60× 1 + 32 (1) × 1
4 = 32 + 32 (1) - 60 × 1
4 = 32(1 + 1) - 60 × 1
4 = 32(2) + 60 (-1)
Instead of x, we have 2 and instead of y, we have -1.
Hence x = 2 and y = -1.
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