if D is the mid point of AC of a right angle triangle ABC Prove that BD=1/2AC
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Step-by-step explanation:
we have, ABC a right angled triangle withB as the right angle
D is a mid point of hypotenuse AC
to prove - BD is half of AC
proof - in triangle ABD and triangle CBD,
AD = DC ( given )
angle. ADB = angle. BDC (90°)
BD = BD (common side)
by SAS rule,
triangle ABD and triangle CBD are congruent
by CPCT,
AC = BD and.
CD = BD
I.e. BD is half of AC
hence proved..
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