Question

if D is the mid point of hyportenuseACof a right angle triangle ABC. prove that BD =1/2AC

Answer 1

AD=dc d is mid point
join bd
in triangle Abo and odb

Ao =bo ( o is mid point of Ab )
Angle o =angle o
od =od (common)
aod =~ odb

so bd = ad (cpct)
ad = dc = bd

bd * ad = Ac
bd +bd = Ac
2bd= ac
bd=1/2ac
hence proved