if D is the mid point of the hypotenuse AC of a right triangle ABC, Prove that BD = ½ AC
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To proof :- BD = 1/2 AC
Proof:- D is the centre of the circle passing through A, B & C
=> AD = BD = CD ( being radii of the same circle)
Or 2AD = 2BD
AC = 2BD
BD = AC/2
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