Question

If D is the midpoint of Hypoteneuse AC of a right-angled triangle ABC\ then show BD=1/2 AC

Answer 1

in triangle ABC , b is a right angle
construction : draw a angle bisector of angle b at d
proof: in ABD and CBD , we have
AC = AC ( COMMON )
<ACD = <CAD ( line AD is a bisector of <B)
AD=AD (COMMON)
ABD CONGRUENT TO ACD
AD=CD=BD
CD=1/2AC ( D is the middle point of AC )
BD=1/2AC .

$hence \: proved \\ please \: mark \: me \: brainly \: and \: follow \: me$

Answer 2

Answer:

BD = 1/2Ac

Step-by-step explanation:

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