If D is the midpoint of the hypotenuse AC of a right angled triangle
ABC, prove that BD = 1/2 AC.
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Step-by-step explanation:
Given:D is the midpoint of the hypothesis AC of a right angled triangle
By Pythagoras theorem
AC^2=AB^2+BC^2
therefore BD=1/2Ac
AC can be written as
(AD+BD)^2=AB^2+BC^2
AD^2+(1/2)^2=AB^2+BC^2
BD = 1/2 AC
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