If D is the midpoint of the hypotenuse AC such that BD = 1/2 AC. Show that ∠ABC is a right angle. PLZZZ
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Step-by-step explanation:
Given that BD=1/2 AC
and D is mid point of AC
Thus BD=AD=CD
In the Δ ABD AD=BD
So ∠A= ∠ABD = p
Similarly in the Δ CBD CD=BD
So ∠C= ∠CBD = q
Thus sum of all three angles of ΔABC
∠A+∠B+∠C=180
p+(p+q) +q=180
2*(p+q)=180°
So p+q=90°
Or ∠ABC=90°
hence proved
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