if d(n)represents number of divisors of n then d(d(18))is
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d(18) = number of divisors of 18
The of divisors are 1, 2, 3, 6, 9, 18
Therefore, Number of divisors of 18 = 6
Therefore, d(18)=6 --------------(1)
Now,
As we have to fine d(d(18))
From result 1 we substitute d(18)=6 in d(d(18))
therefore, Now we have to find d(d(18)) = d(6)
the divisors of 6 = 1, 2, 3, 6
therefore d(6) = 4
Answer:- d(d(18)) = 4
The of divisors are 1, 2, 3, 6, 9, 18
Therefore, Number of divisors of 18 = 6
Therefore, d(18)=6 --------------(1)
Now,
As we have to fine d(d(18))
From result 1 we substitute d(18)=6 in d(d(18))
therefore, Now we have to find d(d(18)) = d(6)
the divisors of 6 = 1, 2, 3, 6
therefore d(6) = 4
Answer:- d(d(18)) = 4
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Answer:
4 .......
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