If D_(p) =| p 15 8 p^(2) 3 9 p^(2) 3 9 p^(3) 25 10 | then (D_(1)+D_(2)+D_(3)+D_(4)+D_(5))/(00)=
Answers
Step-by-step explanation:
Given
D
p
=
∣
∣
∣
∣
∣
∣
∣
∣
p
p
2
p
3
15
35
25
8
9
10
∣
∣
∣
∣
∣
∣
∣
∣
=p(350−225)−15(10p
2
−9p
3
)+8(25p
2
−35p
3
)
D
1
=1(350−225)−15(10(1)
2
−9(1)
3
)+8(25(1)
2
−35(1)
3
)
=125−15.(1)+8(−10)
=125−80−15
=125−95
=30
D
2
=2(350−225)−15(10(2)
2
−9(2)
3
)+8(25(2)
2
−35(2)
3
)
=2.(125)−15(40−72)+8(100−280)
=250+15(32)−1440
=730−1440
=−710
D
3
=3(350−225)−15(10(3)
2
−9(3)
3
)+8(25(3)
2
−35(3)
3
)
=3.(125)−15(90−243)+8(225−945)
=375+15(153)−8(720)
=375+2,295−5760
=−3090.
D
4
=4(350−225)−15(10(4)
2
−9(4)
3
)+8(25(4)
2
−35(4)
3
)
=4.(125)−15(160−576)+8(400−2240)
=500+6240−8.(1840)
=5740−14720
=−8980
D
5
=5(350−225)−15(10(5)
2
−9(5)
3
)+8(25(5)
2
−35(5)
3
)
=5(125)−15(250−1125)+8(625−4375)
=625+13125+(−30,000)
=−16250.
∴D
1
+D
2
+D
3
+D
4
+D
5
=30−710−3090−8980−16250
=−29000.