Question

if d1 and d2 (d2>d1)be the diameters of two concentric circles and c be the length of a chord of a circle which is tangent to other circle prove that d2 square=c square + d square

Answer 1

Given :  d1, d2 (d2>d1) be the diameters of two concentric circles and C be the lengths of a chord of a circle which is tangent to the other circle
To prove : d2= d1 2 + C2
 NowOQ = d2/2 , OR = d1/2 and PQ=c
Since PQ istangent to the circle therefore OR is perpendicular to PQ=> QR = PQ/2 = c/2
 Using pythagorus theorm in triangle OQROQ2 = OR2 + QR2
=> (d2 /2)2
 = (d1/2)2 + (c/2)2
=>1/4 (d2)2
 = 1/4 (d1)2 +(c)2
=> d22 = d12 +c2
Hence Proved

Answer 2

Answer:

here it is .....