If DE || BC, AD = 2x, DC = x+3, BE = 2x-1 & CE = x then find the value of x?
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Answer:
x = 5/3
Step-by-step explanation:
AD = 2x ,DC = x + 3, BE =2x - 1 ,CE = x
Using Thales Theorem
CD/AD = CE/BE
(x+3)/2x = x/(2x-1)
(x+3)(2x-1) = x (2x)
2x^2 -x +6x -3 = 2x^2
2x^2 +5x -3 -2x^2 = 0
5x+3 = 0
x = 5/3
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