Question

if DE is parallel to BC andn AD=1 cm and BD=2 cm. what is the ratio of he area of triangle ABC to the ratio of area of triangle ADE?​

Answer 1

⭐⭐hey mate here your answer ⭐⭐⭐

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Since DE || BC

, by Thales theorem AD/DB = AE/EC

Therefore, both AD/DB

and

AE/EC = 1: 2

So AD:AB = 1:3

or

AB:AD = 3:1

The triangles are similar by SAS axiom. Hence the areas of the triangles are in the ratio of squares of corresponding sides.

Therefore, the ratio of area of Δ ABC to the area of Δ ADE = 3^2:1^2 = 9:1

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Answer 2

Answer:

the ratio is 9:1

I hope you understand