IF DE PARALLEL BC,
CD PARALLEL EF,
THEN PROVE THAT,
AD^2=AB*AF
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Step-by-step explanation:
this question can be solved by using thales theorm corollary or bpt corollary
in ADC,by BPT
we get
af/ad=ae/ac . eq1
in ABC,by BPT
we get
ad/ab=ae/ac . eq2
from 1 and 2
we get
af/ad=ad/ab
by cross multiplying
ad²=af×ab
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