If Deepesh had walked 20 km/h faster he woulh have saved 1 hour in the distance of 60km. what is the usual speed of Deepesh?
A) 100 B) 120 C) 150 D) None of these
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Answer:
100km/h
Step-by-step explanation:
let 'x' be the usual speed
T1-T2=1hrs
time = distance/speed
The distance is same
[600/x] - [600/(x+20)] = 1
600[1/x - 1/(x+20)]=1
600[(x+20-x)/(x²+20x)] =1
we have to simplify and to get the answer as 100km/h
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