If Δ DEF, hypotenuse DF = 6√3. Find the length of seg. EF.
1⃣2√3
2⃣9
3⃣27
4⃣3√3
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If Δ DEF, hypotenuse DF = 6√3. Find the length of seg. EF.
1⃣2√3
2⃣9
3⃣27
4⃣3√3
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