Question

If degree of divisor g(x) is one then the degree of the non-zero remainder r(x) is

Answer 1

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The division algorithm for polynomials over a field gives

p(x)=q(x).g(x)+r(x),

where,

r(x) is the 0 polynomial or deg r(x) < deg g(x).

In the above,

If q(x) is a degree 0 polynomial, then it is a nonzero constant.

Hence, deg p(x) = deg((q(x).g(x)) =deg g(x).

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Answer 2

Answer:

r(x) is the 0 polynomial or deg r(x) < deg g(x). In the above, If q(x) is a degree 0 polynomial, then it is a nonzero constant. Hence, deg p(x) = deg((q(x) please follow me and mark me as a brainliest