If dennis is one-third the age of his father keith now, and was one-fourth the age of his father 5 years ago, then how old will his father keith be 5 years from now ?
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Solution:
Let the present age of Dennis and his father be x and y respectively.
Then, x = y/3 -------- (i)
and (x−5)=(y-5)4 ------- (ii)
On solving both equation we get y= 45 year.
Hence, required age =(y+5)= 50 year
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