Question

If densitu of copper is 8.94 g/cm3 , the no of farraday required to plate an area (20cm * 10 cm) of thivkness of 0.01 cm using CuSO4 as electrolyte is

Answer 1

Volume (V) of Cu = Area x thickness = 10x10 x 1/102 = 1.

d = m/V

m = d x V= 8.94 x 1 = 8.94.

Hence, Actual mass of Cu to be plated is 8.94 g.

Now, Cu2+ + 2e- -------> Cu

So, 2F --------> 63.5 g Cu

       2 x 96500 C -------> 63.5g Cu

                  P  C -------> 8.94 g Cu

                  

P = 2 x 96500 x 8.94/96500

= 27172.

Hence, the answer is 27172