Question

if density of 2.5 M H2SO4 aqueous solution is 1.99 gm m-1 then what will be molality of that solution

Answer 1

Sulfuric acid solution, 2.5M, Honeywell Fluka Chemicals:Acids and Bases:Acids:Sulfuric Acid (H2SO4):General Purpose Sulfuric Acid Solutions.

Answer 2

Answer:

1.4326 m

Explanation:∴molality = Moles of solvent / Weight of solvent(KG)

:- 2.5 M means 2.5 moles in 1000 ml of solution.

1. D=M/V Therefor, M=D*V

mass of the solution is 1.99*1000=1990(g).

    2.Now molality = $\frac{2.5}{1990-2.5*98/1000(TO convert to KG)\\}$

    3. m=2.5÷1745/1000

    4. m=2.5÷1.745

    5. m=1.4326