if density of 20 m/m % of aqueous solution of NaCl(sodium chloride) is 1.05 gm/mole, find the molarity of the solution,
Please explain this question step by step,
And please do not make mistakes, Please..
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Answer:
Correct answer is 3.58M
Explanation:
M= d × 10×W/W% / M.M
M= 1.05 × 10×20 / 58.5 [ 23(Na) + 35.5(Cl) = 58.5]
M = 3.58M
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