Question

if density of CH³OH is 0.80 kg/L find its volume to prepare 2.5l of 0.25M aqueous solution is​

Answer 1

Answer:

Mass of CH3OH required is

M=Volume of solution × Molariy of solution×Molar mass of methanol

=2.5×0.25×32=20 g.

Volume of CH3OH needed = mass/density

=20/0.80

=25ml

hope this helps u...