Question

If det lambda square+3lambda lambda-1 lambda+3 lambda+1 2-lambda lambda-4 lambda-3 lambda+4 3lambda = p lambda power 4+a lambda cube + r lambda square+s lambda+ t then t=

Answer 1

Answer:

Solution

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Correct option is

C

18

To get t,

Put λ=0

We get, value of determinant as,

[0(0+16)+1(0−12)+3(4+6)]=t

=> t=18