Question

If determinant of 1 4 20 1 -2 5 1 2x 5x^2=0,then
find the roots of the determinant.

Answer 1

Answer:

How to solve for exponents

xn=y. Take the log of both sides:logxn=logy. By identity we get:n⋅logx=logy. Dividing both sides by log x: n=logylogx. Find the exponent of a number. ...3n=81. Take the log of both sides:log3n=log81. By identity we get:n⋅log3=log81. Dividing both sides by log 3: n=log81log3.

Step-by-step explanation:

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