If determinant of a is 5 then determinant of adjoint ka is
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A(adj A) = |A|(I)
|A(adj A)| = |(|A| I)|
|A| |adj A| = |A|n∗|I|
|A| |adj A| = |A|n
case 1: if |A|≠0
Then we get ,|adj A| = |A|n−1
case 2: if |A|=0
Then,|adj A|=0
And, we again get |adj A| = |A|n−1
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