Question

if deutrons and alpha particle are accelerated through same potential find the ratio of the associated de broglie wavelength of two​

Answer 1

Using conservation of energy, change in electrostatic energy equals the kinetic energy gained.

E=

2

1

mv

2

=qV

p=mv=

2mqV

1)

De-broglie wavelength is given by: λ=

p

h

λ=

2mqV

h

λ

α

λ

d

=

m

d

q

d

m

α

q

α

λ

alpha

λ

d

=

2×1

4×2

=2

Hence, wavelength of deuteron is more than the wavelength of the alpha particle.