If diagonal of a quadrilateral is 7 cm and the altitudes drawn on the diagonal are 3.5 cm and
2.5 cm, then its area is
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diagonal of a quadrilateral divide it into two traingles
according to the question : sum of the area of two traingles will be the area of quadrilateral
so, area of traingle with base 7cm and height 3.5 cm = 1/2×3.5×7=12.25cm²
area of traingle with base 7cm and height 2.5 cm =1/2×7×2.5=8.75cm²
therefore area of quadrilateral =12.25cm²+8.75cm²=21cm²
here is your answer
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