Question

if diagonal of a square is 10√2 then find perimeter of square
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Answer 1

Step-by-step explanation:

let the sides of square be x

(10√2)^2=x^2+x^2

200=2x^2

x^2=200/2

x^2=100

x=√100

x=10

side of square=10

perimeter=10/4=2.5

Answer 2

Answer:

Let a be the side of sqaure

then,by pythagoras theorem

${daigonal}^{2} = {side }^{2} + {side}^{2}$

${10 \sqrt{2 } }^{2} = {a}^{2} + {a}^{2}$

$200 = 2 {a}^{2}$

$\frac{200}{2} = {a}^{2}$

$a = \sqrt{100}$

a=10

perimeter=4a=40