Question

If diagonal of a square is 13 cm then find it's Side​

Answer 1

Step-by-step explanation:

Using Pythagorous theorem :

let the sides of the square be 'a'

$\implies$ $H^{2}=P^{2}+B^{2}$

$\implies$ $13^{2}=a^{2}+a^{2}$

$\implies$ $169=2a^{2}$

$\implies$ $\sqrt{\Large\frac{169}{2}}=a$

$\implies$ $a={\Large\frac{13}{\sqrt{2}}}$

$\implies$ $a={\Large\frac{13}{\sqrt{2}}}×{\Large\frac{\sqrt{2}}{\sqrt{2}}}$

$\implies$ $\boxed{a={\frac{13\sqrt{2}}{2}}}$

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Answer 2

Step-by-step explanation:

as the diagonal is 13 they bisect at a point and so as it is a square they are perpendicular

therefore half of 13 is 6.5

now take one side of the square and form a triangle inside the square with the diagonals

as the diagonals form a right angle triangle

by Pythagoras theorem

(6.5)square + (6.5)square=(side of the square)hypotenuse suare

42.25+42.25=(hypotenuse)square

84.50=hypotenuse square

√84.50=hypotenuse

9.192..=hypo

:: the side of the square is 9.19